What mass of water is formed during the combustion of 1g. glucose С6Н12О6, if the reaction proceeds according

What mass of water is formed during the combustion of 1g. glucose С6Н12О6, if the reaction proceeds according to the scheme С6Н12О6 + О2 → СО2 + Н2О?

Given:
m (C6H12O6) = 1 g

To find:
m (H2O) -?

Decision:
1) C6H12O6 + 6O2 => 6CO2 + 6H2O;
2) n (C6H12O6) = m (C6H12O6) / M (C6H12O6) = 1/180 = 0.006 mol;
3) n (H2O) = n (C6H12O6) * 6 = 0.006 * 6 = 0.036 mol;
4) m (H2O) = n (H2O) * M (H2O) = 0.036 * 18 = 0.648 g.

Answer: The mass of H2O is 0.648 g.