What mass of water is released during dehydration of 92 g of ethyl alcohol?

Taking into account the data on the condition of the problem, we compose the equation of the process:
С2Н5ОН = С2Н4 + Н2О – dehydration, ethylene, water is released;

Let’s make the calculations:
M (C2H5OH) = 46 g / mol; M (H2O) = 18 g / mol.

Determine the amount of alcohol:
Y (C2H5OH) = m / M = 92/46 = 2 mol;

Y (H2O) = 2 mol since the amount of substances is 1 mol.

Find the mass of the product:
m (H2O) = Y * M = 2 * 18 = 36 g

Answer: the mass of water is 36 g