What mass of water is required to obtain 235 g of nitrous acid from nitric oxide (III)

univerkov | August 8, 2021 | education

Given:
m (HNO2) = 235 g

To find:
m (H2O) -?

1) N2O3 + H2O => 2HNO2;
2) n (HNO2) = m / M = 235/47 = 5 mol;
3) n (H2O) = n (HNO2) / 2 = 5/2 = 2.5 mol;
4) m (H2O) = n * M = 2.5 * 18 = 45 g.

Answer: The mass of H2O is 45 g.

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