What mass of zinc can be obtained from 150 tons of ore containing 88.7% zinc blende (ZnS) if production losses are 6.3%?

1. Let us write down the reaction equations for zinc production:

2ZnS + 3O2 = 2ZnO + 2SO2;

ZnO + H2 = Zn + H2O;

2. find the mass of zinc blende:

m (ZnS) = w (ZnS) * m (ores) = 0.887 * 150 = 133.05 g;

3.Calculate the chemical amount:

n (ZnS) = m (ZnS): M (ZnS);

M (ZnS) = 65 + 32 = 97 g / mol;

n (ZnS) = 133.05: 97 = 1.37 mol;

4. Determine the practical chemical amount of zinc:

npract (Zn) = n (ZnS) * (1 – ν (loss)) = 1.37 * (1 – 0.063) = 1.2827 mol;

5.calculate the mass of zinc:

m (Zn) = n (Zn) * M (Zn) = 1.2827 * 65 = 83.38 g.

Answer: 83.38 g.