What mass of zinc hydroxide can be dissolved in an aqueous solution of sodium hydroxide weighing 20 g.

The equation of the ongoing reaction in solution: Zn (OH) 2 + 2NaOH -> Na2 [Zn (OH) 4]. Note that one portion of zinc hydroxide accounts for two portions of sodium hydroxide. We find the amount of NaOH substance: n (NaOH) = 20/40 = 0.5 mol. This means that half the amount of Zn (OH) 2 enters into the reaction – 0.25 mol. m (Zn (OH) 2) = 0.25 mol * 99 g / mol = 24.75 g.



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