# What mass of zinc must be dissolved in hydrochloric acid so that 14.4 g of copper oxide

What mass of zinc must be dissolved in hydrochloric acid so that 14.4 g of copper oxide can be reduced with the obtained hydrogen (2)

The reduction reaction of copper oxide is described by the following chemical reaction equation.

CuO + H2 = Cu + H2O;

1 mole of metal oxide reacts with 1 mole of hydrogen. In this case, 1 mol of metal and 1 mol of water are synthesized.

Let’s calculate the chemical amount of a substance in 14.4 grams of metal oxide.

M CuO = 64 + 16 = 80 grams / mol;

N CuO = 14.4 / 80 = 0.18 mol;

The same chemical amount of hydrogen will be required.

The reaction between zinc and hydrogen chloride is described by the following chemical reaction equation.

Zn + 2HCl = ZnCl2 + H2;

1 mole of metal reacts with 2 moles of acid. In this case, 1 mol of salt is synthesized and 1 mol of gaseous hydrogen is released.

To obtain 0.18 mol of hydrogen, it is necessary to dissolve 0.18 mol of zinc.

Let’s calculate the mass of the metal.

M Zn = 65 grams / mol;

m Zn = 65 x 0.18 = 11.7 grams; One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.