What masses of acid and alcohol must be taken to obtain 1 g of isobutyl acetate

What masses of acid and alcohol must be taken to obtain 1 g of isobutyl acetate with an ester yield of 60% of the theoretically possible?

Given:
m pract. (isobutyl acetate) = 1 g
η (isobutyl acetate) = 60%

To find:
m (acid) -?
m (alcohol) -?

1) CH3-COOH + CH3-CH (CH3) -CH2-OH => CH3-COO-CH2-CH (CH3) -CH3 + H2O;
2) m theor. (isobutyl acetate) = m practical. * 100% / η = 1 * 100% / 60% = 1.667 g;
3) n (isobutyl acetate) = m / M = 1.667 / 116 = 0.014 mol;
4) n (acid) = n (isobutyl acetate) = 0.014 mol;
5) m (acid) = n * M = 0.014 * 60 = 0.84 g;
6) n (alcohol) = n (isobutyl acetate) = 0.014 mol;
7) m (alcohol) = n * M = 0.014 * 74 = 1.04 g.

Answer: The mass of the acid is 0.84 g; alcohol – 1.04 g