What masses of metallic sodium and bromine are required to obtain sodium bromide NaBr weighing 5.15 g?

The reaction for obtaining sodium bromide: 2Na + Br2 = 2NaBr.
1) Molar mass of sodium bromide: 23 + 80 = 103.
2) The amount of sodium bromide substance: 5.15 / 103 = 0.05 mol.
3) According to the reaction equation, there are two moles of sodium for two moles of sodium bromide. This means that the amount of sodium substance is 0.05 mol.
4) Molar mass of sodium: 23.
5) The mass of sodium is: 23 * 0.05 = 1.15 g – answer 1.
6) According to the reaction equation, there is one mole of bromine for two moles of sodium bromide. This means that the amount of bromine substance is: 0.05 * 2 = 0.1 mol.
7) The molar mass of bromine is: 80.
8) The mass of bromine is: 80 * 0.1 = 8g – answer 2.