What masses of salt and water are formed by the interaction of 23 g of zinc hydroxide with sulfuric acid.

Given:
m (Zn (OH) 2) = 23 g

To find:
m (salt) -?
m (H2O) -?

1) Zn (OH) 2 + H2SO4 => ZnSO4 + 2H2O;
2) n (Zn (OH) 2) = m / M = 23/99 = 0.2 mol;
3) n (ZnSO4) = n (Zn (OH) 2) = 0.2 mol;
4) m (ZnSO4) = n * M = 0.2 * 161 = 32 g;
5) n (H2O) = n (Zn (OH) 2) * 2 = 0.2 * 2 = 0.4 mol;
6) m (H2O) = n * M = 0.4 * 18 = 7 g.

Answer: The mass of ZnSO4 is 32 g; H2O – 7 g.