What masses of salt and water are formed by the interaction of 400 g of 7.3% hydrochloric acid solution with zinc oxide?

Given:
m solution (HCl) = 400 g
ω (HCl) = 7.3%

Find:
m (salt) -?
m (H2O) -?

1) 2HCl + ZnO => ZnCl2 + H2O;
2) m (HCl) = ω * m solution / 100% = 7.3% * 400/100% = 29.2 g;
3) n (HCl) = m / M = 29.2 / 36.5 = 0.8 mol;
4) n (ZnCl2) = n (HCl) / 2 = 0.8 / 2 = 0.4 mol;
5) m (ZnCl2) = n * M = 0.4 * 136 = 54.4 g;
6) n (H2O) = n (HCl) / 2 = 0.8 / 2 = 0.4 mol;
7) m (H2O) = n * M = 0.4 * 18 = 7.2 g.

Answer: The mass of ZnCl2 is 54.4 g; H2O – 7.2 g.