What masses of salt and water are formed by the interaction of phosphoric acid with 60 g of sodium hydroxide.

3NaOH + H3PO4 = Na3PO4 + 3H2O
n (NaOH) = m (NaOH) / M (NaOH) = 60/40 = 1.5 mol, where M (NaOH) = 23 + 16 + 1 = 40 g / mol
It can be seen from the reaction equation that n (H2O) = n (NaOH) = 1.5 mol, and n (Na3PO4) = n (NaOH) / 3 = 1.5 / 3 = 0.5 mol, therefore, m (H2O ) = n (H2O) xM (H2O) = 1.5×18 = 27 g, where M (H2O) = 2×1 + 16 = 18 g / mol
m (Na3PO4) = n (Na3PO4) xM (Na3PO4) = 0.5×164 = 82 g, where M (Na3PO4) = 23×3 + 31 + 16×4 = 164 g / mol