What masses of salt and water are formed by the interaction of phosphoric acid with 60 g of sodium hydroxide.

1) n (NaOH) = 60: 40 = 1.5 mol
2) H3PO4 + 3NaOH = Na3PO4 + 3H2O

coefficients:
H3PO4-1
NaOH-3
Na3PO4-1
H2O-3

3) we compose the ratio of the amounts of substances according to the condition and the equation.
let n (Na3PO4) = x mol:
1.5: 3 = x: 1 x = 0.5 mol

let n (H2O) = y mol:
1.5: 3 = y: 3 y = 1.5 mol

4) Let us find the required quantities by the formulas
m (Na3PO4) = n * M = 0.5 * 164 = 82gram
m (H2O) = n * M = 1.5 * 18 = 27 grams