What material is the spiral of the heating element made of, through which a current of 4 A flows

What material is the spiral of the heating element made of, through which a current of 4 A flows, if its length is 16 m, and the cross section is 0.24 mm2 and the voltage in the network is 120 V.

Coil resistance can be determined by the formula:
R = U / I, where U is voltage (U = 120 V), I is current strength (I = 4 A).
R = U / I = 120/4 = 30 ohms.
We find the density of the spiral material from the formula:
R = (ρ * l) / S, where l is the length of the spiral (l = 16 m), S is the cross-sectional area of the spiral (S = 0.24 mm ^ 2).
Let us express the density of the material from the formula:
ρ = R * S / l = 30 * 0.24 / 16 = 0.45 Ohm * mm ^ 2 / m.
The closest to the obtained value is the density of nickelin ρ = 0.42 Ohm * mm ^ 2 / m.
Answer: The spiral is made of nickel.



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