Given: V0 (initial speed of the train under consideration) = 15 m / s; V (final speed) = 5 m / s; a (acceleration during deceleration) = 2 m / s2.
To determine the distance traveled by the train under consideration when the speed drops, we use the formula: S = (V0 ^ 2 – V ^ 2) / 2a.
Calculation: S = (15 ^ 2 – 5 ^ 2) / (2 * 2) = 50 m.
Answer: When the speed dropped, the train in question covered a distance of 50 meters.
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