What path will a freely falling body travel in 4 s?

The path traversed by the body during uniformly accelerated motion is determined by the formula S = v start * t + (at²) / 2, where S is the path, distance, v start is the initial speed, a is acceleration, t is time.

In our case, we have free fall, that is, a – the acceleration will be equal to the acceleration of gravity – g. And there is no initial speed.

Substitute the known values into the above formula – S = (gt²) / 2, we get – (10 m / s² * (4 s) ²) / 2 = 160 m / 2 = 80 m.

Answer: the path covered by the falling body in 4 seconds will be 80 meters.

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