What path will a person cover in 1 minute if his initial speed is 1 m / s and the acceleration of movement is 0.5 m / s2?

t = 1 min = 60 s.

V0 = 1 m / s.

a = 0.5 m / s2.

S -?

S = (V ^ 2 – V0 ^ 2) / 2 * a, where V, V0 – final and initial speed of movement, a – acceleration of movement.

We express the final speed of movement V from the formula for acceleration: a = (V – V0) / t, where t is the time of speed change.

V = V0 + a * t.

V = 1 m / s + 0.5 m / s2 * 60 s = 31 m / s.

S = ((31 m / s) ^ 2 – (1 m / s) ^ 2) / 2 * 0.5 m / s2 = 960 m.

The path S can also be found by the formula: S = V0 * t + a * t ^ 2/2.

S = 1 m / s * 60 s + 0.5 m / s2 * (60 s) ^ 2/2 = 960 m.

Answer: a person will cover the path S = 960 m.