What path will an initially leaning body with a mass of 3 kg take if a force of 12 Newtons acts on it for 10 seconds?

Given:

m = 3 kg – body weight;

t = 10 s – time during which the force F acts on the body;

F = 12 N – the force acting on the body.

It is required to determine the path S (meters) that the body will pass under the action of the force F.

Let’s calculate the acceleration that the force F will give to the body:

a = F / m = 12/3 = 4 m / s ^ 2.

Taking into account that the body was initially at rest, we will find the traversed path:

S = a * t ^ 2/2 = 4 * 10 * 10/2 = 400/2 = 200 m.

Answer: the body will travel 200 meters.




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