What path will an initially leaning body with a mass of 3 kg take if a force of 12 Newtons acts on it for 10 seconds?
September 12, 2021 | education
| Given:
m = 3 kg – body weight;
t = 10 s – time during which the force F acts on the body;
F = 12 N – the force acting on the body.
It is required to determine the path S (meters) that the body will pass under the action of the force F.
Let’s calculate the acceleration that the force F will give to the body:
a = F / m = 12/3 = 4 m / s ^ 2.
Taking into account that the body was initially at rest, we will find the traversed path:
S = a * t ^ 2/2 = 4 * 10 * 10/2 = 400/2 = 200 m.
Answer: the body will travel 200 meters.
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