What path will the body cover in the eighth second of free fall?

Given:

g = 10 m / s ^ 2 – free fall acceleration;

t = 8 seconds – time span.

It is required to determine what distance S (meter) the body will pass in the 8th second of free fall.

In 8 seconds, the body will cover the distance:

S (8) = g * t ^ 2/2 = 10 * 8 ^ 2/2 = 5 * 8 ^ 2 = 5 * 64 = 320 meters.

In 7 seconds, the body will cover the distance:

S (7) = g * t ^ 2/2 = 10 * 7 ^ 2/2 = 5 * 7 ^ 2 = 5 * 49 = 245 meters.

Then, in the eighth second, the body will pass:

S = S (8) – S (7) = 320 – 245 = 75 meters.

Answer: in the eighth second of free fall, the body will cover a path equal to 75 meters.