What path will the plane take to stop if its acceleration during deceleration was exactly 4 m / s2

What path will the plane take to stop if its acceleration during deceleration was exactly 4 m / s2, and its speed at the moment of deceleration was 40 m / s?

We are given: a = -4 m / s2
Vo = 40 m / s V = 0.
S = (V ^ 2-Vo ^ 2) / 2 * a = -Vo ^ 2/2 * a = -40 * 40 / -2 * 4 = 200 m
Answer: the plane will cover a distance of 200 meters



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