What power does an athlete weighing 75 kg develop during a high jump

What power does an athlete weighing 75 kg develop during a high jump, if during a jump his center of gravity rises by 1.3 m, and the continuation of a push is 0.2 s?

Given:

m = 75 kilograms – athlete’s weight;

g = 9.8 N / kg (Newton per kilogram) – acceleration of gravity;

h = 1.3 meters – the height to which the athlete’s center of gravity rises during a high jump;

t = 0.2 seconds – duration of the push.

It is required to determine W (Watt) – what power the athlete develops.

Let’s find the force of gravity acting on the athlete:

F = 75 * 9.8 = 735 Newton.

Then the work done by the athlete will be equal to:

A = F * h = 735 * 1.3 = 955.5 Joules.

Then the power will be equal to:

W = A / t = 955.5 / 0.2 = 4777.5 watts.

Answer: the power developed by the athlete is 4777.5 watts (approximately 4.8 kW).



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