What power does the force develop with uniform lifting of a load weighing 100 kg to a height of 0.5 m in 0.4 s?


m = 100 kilograms is the mass of the load lifted by a certain force;

g = 9.8 N / kg (Newton per kilogram) – acceleration of gravity;

h = 0.5 meters – the height to which the load is lifted;

t = 0.4 seconds – the time to lift the load.

It is required to determine W (Watt) – the power developed by the force.

Since, according to the condition of the problem, the load is lifted uniformly, the magnitude of the force will be equal to the force of gravity acting on the load:

F = m * g = 100 * 9.8 = 980 Newton.

Then the work done by force will be equal to:

A = F * h = 980 * 0.5 = 490 Newton.

Then the power will be equal to:

W = A / t = 490 / 0.4 = 4900/4 = 1225 watts.

Answer: the power developed by the force is 1225 watts (approximately 1.2 kW).

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