What power of the electric current is released in the section of the circuit with an electrical resistance of 2
| September 25, 2021 | education
What power of the electric current is released in the section of the circuit with an electrical resistance of 2 Ohms at a voltage of 12 V and what work does the electric current do in this section of the price for 15 minutes.
The allocated power of the circuit section is determined by the formula P = U ^ 2 / R where P is the power, U is the voltage, R is the resistance.
P = 12 ^ 2/2 = 144/2 = 72 W.
The work done by the current during the time t is defined as: A = P * t, where P is the allocated power, then we get (we will translate the time into hours 15 minutes = 1/4 hour):
A = 72 * 1/4 = 18 J.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
