What pressure does a 60 kg student exert on the floor while standing on the floor if the surface

What pressure does a 60 kg student exert on the floor while standing on the floor if the surface area of her soles is 400 cm ^ 2?

Problem data: m (student’s weight) = 60 kg; S (surface area of the student’s soles) = 400 cm2 (SI S = 0.04 m2).

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

The required pressure, which the student exerts on the floor, is determined by the formula: P = Fт / S = m * g / S.

Let’s perform the calculation: P = 60 * 10 / 0.04 = 15 * 10 ^ 3 Pa = 15 kPa.

Answer: The student applies a pressure of 15 kPa to the floor.