What pressure does a 6m ^ 3 granite column exert if its height is 4m?

Given:

V = 6 cubic meters – the volume of the granite column;

h = 4 meters – the height of the granite column;

ro = 2600 kilograms per cubic meter – the density of granite.

It is required to determine P (Pascal) – what pressure the granite column exerts on the support.

Find the support area of ​​the granite column:

s = V / h = 6/4 = 1.5 m2.

The force of gravity acting on a granite column will be equal to:

F = m * g (where g = 10 Newton / kilogram is an approximate value);

F = ro * V * g = 2600 * 6 * 10 = 2600 * 60 = 156000 Newtons.

Then the pressure will be equal to:

P = F / s = 156000 / 1.5 = 104000 Pascal = 104 kPa.

Answer: a granite column produces a pressure of 104 kPa on the floor.