What pressure does a 6m3 granite column exert on the ground if its base area is 1.5 m2.

Given:
V = 6 m3 – the volume of the granite column;
s = 1.5 m2 – the area of ​​the base of the granite column;
ro = 2600 kilograms per cubic meter – the density of granite.
It is required to determine P (Pascal) – what pressure the granite column exerts on the ground.
Find the mass of the granite column:
m = ro * V = 2600 * 4 = 10400 kilograms.
The force of gravity acting on a granite column will be equal to:
F = m * g (where g = 10 Newton / kilogram is an approximate value);
F = 10400 * 10 = 104000 Newton.
Then the pressure will be equal to:
P = F / s = 104000 / 1.5 = 69333 Pascal (approximately 63.3 kPa).
Answer: a granite column produces a pressure of 63.3 kPa on the floor.

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