What pressure does a body weighing 0.6 tons and an area of 3m ^ 2 exert on the floor?

m = 0.6 t = 600 kg;

S = 3 m2;

g = 9.8 N / kg;

R – ?

To find the pressure exerted by the body on the floor, we use the formula p = F / S, where p is the pressure, F is the force acting perpendicular to the surface, S is the surface area.

Since the force F = mg, then p = mg / S.

p = (600 kg * 9.8 N / kg) / 3 m2 = 1960 Pa = 1.96 kPa.

Answer: the body exerts a pressure equal to 1.96 kPa.