# What pressure does a four-axle railroad car weighing 50 tons exert on the railroad bed

What pressure does a four-axle railroad car weighing 50 tons exert on the railroad bed if the contact area of one wheel with the rail is 5 cm2?

Initial data: m (mass of a four-axle railway carriage) = 50 t; S1 (the area of contact of one wheel with the rail, a four-axle car has eight wheels) = 5 cm2.

Constants: g = 10 m / s2.

SI system: m = 50 t = 50 * 10 ^ 3 kg; S1 = 5 cm2 = 5 * 10 ^ -4 cm2.

The pressure exerted by the car on the railroad bed: P = F / S = m * g / 8S1.

Calculation: P = 50 * 10 ^ 3 * 10 / (8 * 5 * 10 ^ -4) = 125 * 106 Pa or 125 MPa.

Answer: A four-axle wagon exerts a pressure of 125 MPa on the railroad bed.

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