What pressure does a marble column produce on the support, the volume of which is 7m3

What pressure does a marble column produce on the support, the volume of which is 7m3, if the base area is 1.4m²? Density of marble = 2.7g / cm³

V = 7 m3.

S = 1.4 m2.

ρ = 2.7 g / cm3 = 2700 kg / m3.

g = 10 N / kg.

P -?

The pressure of the marble column P will be the ratio of the pressure force of the column F to the area of ​​its base S: ​​P = F / S. The column acts on its base by the force of its weight F, the value of which is expressed by the formula: F = m * g, where m is the mass of the marble column, g is the acceleration of gravity.

We express the mass of the column m by the formula: m = V * ρ, where V is the volume of the marble column, ρ is the density of the marble.

F = V * ρ * g.

The pressure of the marble column will be determined by the formula: P = V * ρ * g / S.

P = 7 m3 * 2700 kg / m3 * 10 N / kg / 1.4 m2 = 135000 Pa = 135 kPa.

Answer: a marble column produces a pressure of P = 135 kPa on the support.



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