What pressure does a person experience at a depth of 100m if the density of seawater is 1030 kg / m3?

Given:

h = 100 meters – the depth at which the person is;

g = 9.8 meters per second squared – gravitational acceleration (constant near the surface of the earth;

ro = 1030 kilograms per cubic meter – the density of seawater.

It is required to determine P (Pascal) – what pressure a person will experience at a sea depth equal to h.

To determine the pressure, you must use the following formula:

P = ro * g * h = 1030 * 9.8 * 100 = 10094 * 100 = 1009400 Pascal (approximately 1 MPa).

Answer: the pressure will be equal to 1009400 Pascal.