What pressure is exerted by a body weighing 400 kg if the support area is 20 dm2?
| March 8, 2021 | education
Data: m (weight of the indicated body) = 400 kg; S (support area) = 20 dm2 = 0.2 m2; g (acceleration due to gravity) ≈ 10 m / s2.
The pressure exerted by the specified body: P = Ft / S = m * g / S = 400 * 10 / 0.2 = 20 * 10 ^ 3 Pa = 20 kPa.
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