What pressure is exerted by a person on one leg weighing 55 kg with a leg size of 202 cm3

To find out the pressure exerted by the person represented, consider the formula: Px = Ft / Sop = mh * g / Sn, where mh is the mass of the person represented (mh = 55 kg); g – acceleration due to gravity (g ≈ 9.8 m / s2); Sн – support leg area (Sн = 202 cm2 = 202 * 10 ^ -4 m2).

Let’s perform the calculation: Px = mh * g / Sn = 55 * 9.8 / (202 * 10 ^ -4) ≈ 26.7 * 10 ^ 3 Pa.

Answer: The design pressure exerted by the person represented is 26.7 kPa.



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