What pressure is exerted on the bottom of the vessel by a layer of kerosene 50 cm high?

What pressure is exerted on the bottom of the vessel by a layer of kerosene 50 cm high (the density of kerosene is 800 / m3)?

Given:

h = 50 centimeters – the height of the column of kerosene in the vessel;

g = 10 Newton / kilogram – acceleration of gravity;

ro = 800 kilograms / cubic meter – density of kerosene.

It is required to determine P (Pascal) – what pressure is exerted by a column of kerosene on the bottom of the vessel.

Let’s convert the units of measurement of length from centimeters to meters:

h = 50 cm = 50 * 10-2 = 50/100 = 0.5 meters.

Then the pressure of the column of kerosene at the bottom of the vessel is found by the following formula:

P = ro * g * h = 800 * 10 * 0.5 = 800 * 5 = 4000 Pascal (4 kPa).

Answer: a column of kerosene exerts a pressure of 4000 Pascal (4 kPa) on the bottom of the vessel.