What pressure is exerted on the ground by a granite column with a volume of 6 m ^ 3

What pressure is exerted on the ground by a granite column with a volume of 6 m ^ 3, the base area of which is 1.5 m ^ 2

Initial data: V (volume of the granite column) = 6 m3; S (base area of a granite column) = 1.5 m2.

Reference values: g (acceleration due to gravity) = 10 m / s2; ρ (density of granite) = 2600 kg / m3.

The pressure that the granite column will exert on the soil can be calculated by the formula: P = Ft / S = m * g / S = ρ * V * g / S.

Let’s calculate: P = 2600 * 6 * 10 / 1.5 = 104,000 Pa or 104 kPa.

Answer: The granite column will exert a pressure of 104 kPa on the ground.