What pressure is exerted on the ground by a marble column with a volume of 8 m3, if the base area is 0.54 m2?

Initial data: V (volume of the marble column) = 8 m3; S (area of the base of the marble column) = 0.54 m2.

Reference values: according to the condition of the problem ρ (density of marble) = 2700 kg / m3; g (acceleration due to gravity) = 10 m / s2.

The pressure of the marble column on the ground is determined by the following formula: P = F / S = m * g / S = ρ * V * g / S.

Calculation of ground pressure: P = 2700 * 8 * 10 / 0.54 = 400,000 Pa or 400 kPa.

Answer: The marble column exerts a pressure of 400 kPa on the ground.