What pressure is exerted on the ice by a skater weighing 60 kg on the ice if the width of the skate

What pressure is exerted on the ice by a skater weighing 60 kg on the ice if the width of the skate blade is 4 mm and the length is 30 cm?

m = 60 kg.

g = 9.8 m / s ^ 2.

a = 4 mm = 0.004 m.

l = 30 cm = 0.3 m.

P -?

The pressure of the force P is the ratio of the force F to the area S on which this force acts: P = F / S.

The skater presses on the ice with his weight F, the value of which is determined by the formula: F = m * g.

The contact surface of the skate with the ice will be considered in the form of a rectangle, so the area of contact of the skate with the ice will be expressed by the formula: S1 = a * l.

Since the skater has 2 skates, then S = 2 * S1.

P = m * g / 2 * a * l.

P = 40 kg * 9.8 m / s ^ 2/2 * 0.004 m * 0.3 m = 163333 Pa.

Answer: the skater puts pressure on the ice P = 163333 Pa.