What pressure is produced by a column of mercury 1mm high, a column of water of the same height?

Given:

h = 1 millimeter = 0.001 meter – the height of the columns of mercury and water;

ro1 = 1000 kg / m ^ 3 – water density;

ro2 = 13540 kg / m ^ 3 is the density of mercury;

g = 10 m / s ^ 2 – acceleration of gravity.

It is required to determine the pressure of the columns of water and mercury P1 and P2 (Pascal).

The pressure that the water column produces:

P1 = ro1 * g * h = 1000 * 10 * 0.001 = 10 Pascal.

The pressure that the column of mercury produces:

P2 = ro2 * g * h = 13540 * 10 * 0.001 = 135.4 Pascal.

Answer: A column of mercury produces a pressure of 135.4 Pascal; a column of water produces a pressure of 10 Pascal.