What pressure should a 50L gas cylinder withstand so that at a temperature of 25 it can store 2 kg of methane (CH4).

univerkov | January 15, 2021 | education

Data: V (volume of the gas cylinder) = 50 l = 50 * 10-3 m3; T (absolute temperature of methane) = 25 ºС = 298 K; m (mass of methane) = 2 kg.
Constants: M (molar mass of methane) = 16.04 g / mol = 16.04 * 10-3 kg / mol; R (universal gas constant) = 8.31 J / (mol * K).
The pressure that the balloon must withstand is calculated using the Mendeleev-Clapeyron law: P * V = (m / M) * R * T and P = m * R * T / (V * M).
Calculation: P = 2 * 8.31 * 298 / (50 * 10-3 * 16.04 * 10-3) ≈ 6.18 * 106 Pa = 6.18 MPa.

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