What pressure should the pump develop to ensure the rise of water from the 934m horizon to the 300m horizon?

Initial data: h1 (depth of the first horizon) = 934 m; h2 (depth of the second horizon) = 300 m.

Reference data: g (acceleration due to gravity) = 9.81 m / s2; ρ (density of the lifted water) = 1000 kg / m3.

The pressure that the pump must develop is determined by the formula: Р = ρ * g * Δh = ρ * g * (h1 – h2).

Calculation: P = 1000 * 9.81 * (934 – 300) = 6 219 540 Pa ≈ 6.2 MPa.

Answer: The pump must develop a pressure of 6.2 MPa.