What self-induction emf occurs in a coil with an inductance of 60 mH if the current of 4 A
| July 24, 2021 | education
What self-induction emf occurs in a coil with an inductance of 60 mH if the current of 4 A in it decreases to zero in 0.02 s?
To find the value of the self-induction EMF that has arisen in the presented coil, consider the formula: | εsi | = L * ΔI / Δt = L * (I – I0) / Δt, where L is the inductance of the presented coil (L = 60 mH = 0.06 H); I – final current (I = 0 A); I0 – initial current (I0 = 4 A); Δt is the time of EMF occurrence (Δt = 0.02 s).
Calculation: εsi | = L * (I – I0) / Δt = 0.06 * (0 – 4) / 0.02 = 12 V.
Answer: The self-induction EMF arising in the presented coil should be 12 V.
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