What should be the cross-sectional area of a copper conductor 2m long so that when a current

| February 14, 2021 | education

What should be the cross-sectional area of a copper conductor 2m long so that when a current of 150A passes through it, the voltage at its ends is 6V

L = 2 m.

I = 150 A.

ρ = 0.017 Ohm * mm2 / m.

U = 6 V.

S -?

The resistance R of a cylindrical homogeneous copper conductor is determined by the formula: R = ρ * L / S, where ρ is the resistivity of copper, L is the length of the conductor, S is the cross-sectional area of ​​the conductor.

We express the resistance of the same conductor R from Ohm’s law for a section of the circuit by the ratio of the voltage at its ends U to the current in the conductor: R = U / I.

ρ * L / S = U / I.

The cross-sectional area of ​​the conductor S will be determined by the formula: S = ρ * L * I / U.

S = 0.017 Ohm * mm2 / m * 2 m * 150 A / 6 V = 0.85 mm2.

Answer: The cross-sectional area of ​​the copper conductor is S = 0.85 mm2.



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