What speed does a body weighing 3 kg acquire under the action of a force equal to 9 N after 5 s?

1) We calculate the constant acceleration of the body, applying Newton’s second law for calculations:

F = m * a, where F is the force acting on the body (F = 9 N), m is the body weight (m = 3 kg), a is the constant acceleration of the body.

a = F / m = 9/3 = 3 m / s2.

2) Let us calculate the speed of the body after 5 s (t = 5 s), assuming that the body began to move from a state of rest:

V = a * t = 3 * 5 = 15 m / s.

Answer: Moving for 5 s, the body will acquire a speed of 15 m / s.