What speed does a rocket acquire, moving from rest with an acceleration of 2 m / s ^ 2, on a path of 1600 m?

Initial data: V0 (initial velocity of the rocket) = 0 m / s (movement from rest); a (rocket acceleration) = 2 m / s2; S (the path covered by the rocket) = 1600 m.

The speed that the rocket will acquire at the end of the given path can be expressed from the formula: S = (V ^ 2 – V0 ^ 2) / 2a = V ^ 2 / 2a, whence V ^ 2 = S * 2a and V = √ (S * 2a ).

Let’s make the calculation: V = √ (1600 * 2 * 2) = 80 m / s.

Answer: Having overcome 1600 meters, the rocket will develop a speed of 80 m / s.