What speed does a stationary boat prevail, the mass of which with a weighting agent is 200 kg

What speed does a stationary boat prevail, the mass of which with a weighting agent is 200 kg, if the passenger in it makes a shot in the direction of the stern. Cartridge mass 10 grams. Initial speed 800m / s

The boat speed can be calculated using the momentum conservation law:

m1V1 = m2V2, where m1 is the mass of the boat with a weighting agent, the mass of the bullet can be neglected (m1 = 200 kg), V1 is the speed that the boat will acquire after the shot (m / s), m2 is the mass of the bullet (m2 = 10 g = 0, 01 kg), V2 – bullet speed (V2 = 800 m / s).

Let’s express and calculate the speed of the boat:

V1 = m2V2 / m1 = 800 * 0.01 / 200 = 8/200 = 0.04 m / s.

Answer: After the shot, the boat acquired a speed of 0.04 m / s.



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