What speed should an artificial Earth satellite rotate at a height equal to the Earth’s radius above the Earth’s surface?

univerkov | December 14, 2020 | education

The law of gravitation: F = kMm / R ^ 2 = mg
kM / R ^ 2 = g
mv ^ 2 // (2R) = kMm / (2R) ^ 2
v ^ 2 / (2R) = g / 4
v ^ 2 = 2gR
v = √ (2gR)
v = √ (2 • 9.8 • 6400 • 10 ^ 3) = √ (2 • 0.98 • 64 • 10 ^ 6) = 1.4 • 8 • 10 ^ 3 = 11 • 10 ^ 3 (m / s) = 11 km / s

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