What speed will a projectile with a mass of 0.1 kg acquire under the action of a spring with a stiffness

What speed will a projectile with a mass of 0.1 kg acquire under the action of a spring with a stiffness of 40 N / m, compressed by 5 cm?

Initial data: m (projectile mass) = 0.1 kg; k (compressed spring stiffness) = 40 N / m; Δl (spring deformation value) = 5 cm.

SI system: Δl = 5 cm = 0.05 m.

Since the deformation energy of the spring will go into the kinetic energy of the projectile, the equality will be true: 0.5 * m * V ^ 2 = 0.5 * k * Δl ^ 2, whence V = √ (k * Δl ^ 2 / m).

Let’s calculate: V = √ (40 * 0.05 ^ 2 / 0.1) = 1 m / s.

Answer: The projectile under the action of a spring will acquire a speed of 1 m / s.