What speed will a rocket move from rest with an acceleration of 60 m / s on a path of 3 km?

If we assume that the rocket is moving uniformly accelerated, then the formula for the path traveled by the rocket is:
S = (V² – V0²) / 2a, where S is the path traveled by the rocket (S = 3 km = 3000 m), V is the final speed of the rocket (m / s), V0 is the initial speed of the rocket (V0 = 0 m / s ( acceleration occurred from a state of rest)), and – rocket acceleration (a = 60 m / s²).
Let’s express and calculate the final velocity of the rocket:
S = (V² – V0²) / 2a = V² / 2a.
V = √ (S * 2a) = √ (3000 * 2 * 60) = √ (360000) = 600 m / s.
Answer: The rocket will acquire a speed of 600 m / s.