What substances and in what mass will the solution contain after the reaction of 5 g

What substances and in what mass will the solution contain after the reaction of 5 g of iron with 150 g of a 30% hydrochloric acid solution?

Given:
m (Fe) = 5 g
m (HCl) = 150 g
ω (HCl) = 30%

To find:
m (in-in) -?

1) Fe + 2HCl => FeCl2 + H2;
2) n (Fe) = m / M = 5/56 = 0.09 mol;
3) m (HCl) = ω * m solution / 100% = 30% * 150/100% = 45 g;
4) n (HCl) = m / M = 45 / 36.5 = 1.23 mol;
5) n react. (HCl) = n (Fe) * 2 = 0.09 * 2 = 0.18 mol;
6) n rest. (HCl) = n (HCl) – n re. (HCl) = 1.23 – 0.18 = 1.05 mol;
7) m rest. (HCl) = n rest. * M = 1.05 * 36.5 = 38.3 g;
8) n (FeCl2) = n (Fe) = 0.09 mol;
9) m (FeCl2) = n * M = 0.09 * 127 = 11.4 g.

Answer: The mass of HCl is 38.3 g; FeCl2 – 11.4 g.