What temperature T has a mass m = 5 of nitrogen occupying a volume of V = 345 cm3 at a pressure of p = 2 MPa?

Given:

m (N2) = 5 kg;

M (N2) = 0.028 kg / mol is the molar mass of nitrogen;

V = 345 cm ^ 3 = 345 * 10 ^ -6 m ^ 3;

p = 2 MPa = 2 * 10 ^ 6 Pa;

T -?

let’s use the Cliperon-Mendeleev equation:

p * V = m / M RT; From this formula, T is equal to:

T = p * V * M / (m * R);

T = 2 * 10 ^ 6 * 345 * 10 ^ -6 * 0.028 / (5 * 8.31) = 19.32 / 41.55 = 0.46 K