What temperature will the water get if you mix 0.02 kg of water at 15 degrees, 0.03 kg of water at 25 degrees?
| August 5, 2021 | education
mх = 0.02 kg.
tx = 15 ° C.
mg = 0.03 kg.
tg = 25 ° C.
t -?
When mixing water of different temperatures, due to heat exchange, water with a higher temperature will give a certain amount of heat to water with a lower temperature: Qg = Qx.
Qg = C * mg * (tg – t).
Qx = C * mx * (t – tx).
C * mg * (tg – t) = C * mх * (t – tх) – heat balance equation.
mg * tg – mg * t = mх * t – mх * tх.
mх * t + mg * t = mg * tg + mх * tх.
t = (mg * tg + mx * tx) / (mx + mg).
t = (0.03 kg * 25 ° C + 0.02 kg * 15 ° C) / (0.02 kg + 0.03 kg) = 21 ° C.
Answer: when mixing water, a temperature of t = 21 ° C will be established.
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