What temperature will the water have if you mix 400 kg of water at 20C with 100 kg of water at 70C?
| September 19, 2021 | education
m1 = 400 kg.
C = 4200 J / kg * ° C.
t1 = 20 ° C.
m2 = 100 kg.
t2 = 70 ° C.
t -?
Q1 = Q2.
Q1 = C * m1 * (t – t1).
Q2 = C * m2 * (t2 – t).
C * m1 * (t – t1) = C * m2 * (t2 – t).
m1 * t – m1 * t1 = m2 * t2 – m2 * t.
m1 * t + m2 * t = m2 * t2 + m1 * t1.
t = (m2 * t2 + m1 * t1) / (m1 + m2).
t = (100 kg * 70 ° C + 400 kg * 20 ° C) / (400 kg + 100 kg) = 30 ° C.
Answer: when mixing water, a temperature of t = 30 ° C will be established.
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